8.3 8 Create Your Own Encoding Codehs Answers -

statement in your loop. If the user types a space or a "!", your program shouldn't crash; it should just add that character to the final string unchanged. Efficiency:

// The encoding function function encode(text) let result = ""; for (let i = 0; i < text.length; i++) // Shift the character code by 1 let charCode = text.charCodeAt(i) + 1; result += String.fromCharCode(charCode); return result; // The decoding function function decode(encodedText) let result = ""; for (let i = 0; i < encodedText.length; i++) // Shift the character code back by 1 let charCode = encodedText.charCodeAt(i) - 1; result += String.fromCharCode(charCode); return result; // Main program to test function start() let original = "Hello CodeHS"; let secret = encode(original); let backToNormal = decode(secret); console.log("Original: " + original); console.log("Encoded: " + secret); console.log("Decoded: " + backToNormal); Use code with caution. Common Pitfalls to Avoid

Here is a breakdown of how to approach the code and the logic behind it. 8.3 8 create your own encoding codehs answers

Use if/elif/else statements to check if a character needs to be changed.

Match the exact text requested by the assignment description inside your input() function. Extra spaces or missing colons can trigger a grading error. statement in your loop

alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ " def encode_custom(msg): return [alphabet.index(ch.upper()) for ch in msg if ch in alphabet]

Decoding is more subtle because binary strings have no separators. The function must: Use if/elif/else statements to check if a character

| Mistake | Symptom | Fix | |---------|---------|-----| | Using ord(ch) directly | Decoding returns original numbers, not letters | Must create reverse mapping | | Forgetting case sensitivity | 'A' and 'a' map differently | Use .lower() or handle both | | Spaces as 0 or 32 | Confusion between index 0 and space character | Pick a consistent special value (e.g., 27) | | Not handling unknown chars | Crash on punctuation | Add a default (e.g., 99 for ‘?’) |

You need to create a function that takes a string and replaces each letter with a corresponding value from a "code" dictionary. If a character isn’t in your dictionary (like a space or punctuation), you typically keep it as is. Sample Solution (Python)